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Matches 1 to 3 of 3 for Last Name equals BRINKMANN AND Tree equals Suedpfalz

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 #  Last Name, Given Name(s)    Person ID   Born/Christened    Location 
1
Brinkmann
I407490    
2
Brinkmann, Marc
I407491    
3
Brinkmann, Rosa
I166789  b. 1 Mar 1909 Ferdinand, Dubois County, Indiana, USA  

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