Search Results
Matches 1 to 3 of 3 for Last Name equals BRINKMANN AND Tree equals Suedpfalz
# | Last Name, Given Name(s) | Person ID | Born/Christened | Location |
---|---|---|---|---|
1 |
Brinkmann | I407490 | ||
2 |
Brinkmann, Marc | I407491 | ||
3 |
Brinkmann, Rosa | I166789 | b. 1 Mar 1909 | Ferdinand, Dubois County, Indiana, USA |