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Matches 1 to 2 of 2 for First Name contains VALENTINE FRANK AND Tree equals Suedpfalz

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 #  Last Name, Given Name(s)    Person ID   Born/Christened    Location 
1
Brown, Valentine Frank
I68013  b. 7 Sep 1918 Millvale, Allegheny County, Pennsylvania, USA  
2
Hoffman, Valentine Frank "Val"
I237602  b. 16 Apr 1904 Richardton, Stark County, North Dakota, USA  

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